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A body of mass 2 kg is tied to the end o...

A body of mass 2 kg is tied to the end od a string 2 m long and revolved in horizontal circle .If the breaking tension of the string is 400 N, then the maximum velocity of the body will be

A

20

B

30

C

40

D

60

Text Solution

Verified by Experts

The correct Answer is:
B
`T=(mv^(2))/(r ) = mr omega ^(2 ) = mr . 4 pi ^(2) n^(2) `
` therefore n^(2) = (T )/( 4 pi ^(2) m r) =(10)/(4xx10xx1xx1)`
` therefore n^(2) =(1)/(4) therefore n= (1)/(2) `
` therefore ` no. Of revolutions / minute `=60xx(1)/(2) = 30 `
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