Home
Class 12
PHYSICS
A proton of mass 1.6 xx 10^(-27)kg goes...

A proton of mass `1.6 xx 10^(-27)kg` goes round in a circular orbit of radius 0.10 m under a centripetal force of `4 xx 10^(-13) N`. then the frequency of revolution of the proton is about

A

`3xx10^(7) rad//s`

B

`4xx10^(7) rad//s`

C

`5xx10rad//s`

D

`8xx10^(7) rad//s`

Text Solution

Verified by Experts

The correct Answer is:
C
`F= (mv^(2))/(r ) = mr omega ^(2)`
` therefore omega ^(2) =(F)/(mr) = ( 4xx10 ^(-13))/(1.6xx10^(-27)xx10^(-1))`
` therefore omega ^(2) = 25xx10^(14) therefore omega = 5xx10^(7) rad //s`
Promotional Banner

Topper's Solved these Questions

  • CIRCULAR MOTION

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP-1|1 Videos

  • CIRCULAR MOTION

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP-2|1 Videos

  • ATOMS, MOLECULES AND NUCLEI

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|30 Videos

  • COMMUNICATION SYSTEMS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP -20|10 Videos

Similar Questions

Explore conceptually related problems

A proton of mass 1.6times10^-27 kg goes round in a circular orbit of radius 0.12 m under a certripetal force of 6 times 10^-14 N. then the frequency of revolution of the proton is about

An electron of mass 9xx10^(-31)kg moves around a nucleus in a circular orbit of radius 2A^(@) under the action of centripetal force 3.2N. Then the equivalent electric current is

An electron has a mass of 9.1 xx 10^(-31)kg . It revolves round the nucleus in a circular orbit of radius 0.529 xx 10^(-10) metre at a speed of 2.2 xx 10^(6) m//s . The magnitude of its linear momentum in this motion is

A electron of mass 9xx10^(-31) kg is revolving in a stable circular orbit or radius 1.8xx10^(-12) m in a hydrogen atom. If the electrostatic froce of attraction between the proton and electron is 8xx10^(-8) N, the velosity of the electron is

A proton of mass 1.66 xx 10^(-27) kg is moving with kinetic energy 5 xx 10^(-17) J .What is the wavelength of proton ?

The earth of mass 6xx10^(24)kg revolves round the sun with angular velocity 3xx10^(-7)"rad/s" in a circular orbit of radius 1.5xx10^(8)km. Then the force exerted by the sun on the earth in newtons, is

An electron with mass 9.1xx10^(-31) kg moves with a speed of 2xx10^(6)m//s in a circle of 2.85 cm radius under the influence of magnetic field. A protons of mass 1.67xx10^(-27) kg moving in the same plane with the same speed, experiences the same centripetal force. What is the radius of the proton's orbit?

A satellite of mass 200 kg revolves around of mass 5 xx 10^(30) kg In a circular orbit of radius 6.6 xx10^(6) m . Binding energy of the satellite is

In a hydrogen atom an electron of mass 9.1 xx 10^(-31) jg revolves about a proton in circular orbit of radius 0.53 Å . Calculate the radial acceleration and angular velocity of electron. [8.9 xx 10^(22) m//s^(2), 4.1 xx 10^(16)s^(-1)]

An electron is moving in a circular orbit of radius 5.3xx10^(-11) metre around the atomic nucleus at a rate of 6.6xx10^(15) revolutions per second. The centripetal force acting on the electron will be - (The mass of the electron is 9.1xx10^(-31) kg)