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A small coin is kept at the rim of a h...

A small coin is kept at the rim of a horizontal circular disc which is set into rotation about verticle axis passing through its centre. If radius of the disc is `5 cm and mu_(s)=0.25`, then the angular speed at which the coin will just slip off at

A

2rad /s

B

3 rad/s

C

5 rad/s

D

4 rad/s

Text Solution

Verified by Experts

The correct Answer is:
D
C.P force = maximum frictional force
` therefore m r omega = mu R = mu g `
` therefore omega ^(2) = 25 xx10^(14) therefore omega =(mu g) /( r ) = ( 0.2xx10)/(12.5xx10^(-2))`
` therefore omega ^(2) = 16 therefore = 4 rad //s`
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