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From the ceiling of a train, a pendulum ...

From the ceiling of a train, a pendulum of length 'l' is suspended. The train is moving with an acceleration `a_(0)` on horizontal surface. What must be the period of oscillation of pendulum?

A

`T=2pi sqrt((l)/(g))`

B

`T=2pi sqrt((l)/(g+a))`

C

`T=2pi sqrt((l)/((g^(2)+a^(2))^(1//2)))`

D

`T=2pi sqrt((l)/((g^(2)-a^(2))^(1//2)))`

Text Solution

Verified by Experts

The correct Answer is:
C
As g and a are perpendicular to each other
` therefore ` Net acceleration `= sqrt( g^(2) +a^(2))`
` therefore T=2pi sqrt((l)/((sqrt((g^(2)+a^(2))^(1//2)))`
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