A paticle of mass `m` is executing uniform circular motion on a path of radius `r`. If `p` is the magnitude of its linear momentum, then the radial force acting on the particle is
A
`(P) /(mr^(2))`
B
`(p^(2))/(mr)`
C
`(pm)/(r )`
D
`(p^(2)r)/(m)`
Text Solution
Verified by Experts
The correct Answer is:
B
`(mv^(2))/( r ) =( m^(2) v^(2))/(mr) =(p^(2))/(mr)`
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