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If acycle wheel of radius 0.4 m comp...

If acycle wheel of radius 0.4 m completes one revolution in one second , then the acceleration of a point on the rim is in one second , then the acceleration of a point on the rim is

A

`0.8 pi ^(2) m//s^(2)`

B

`1.2pi ^(2) m//s^(2)`

C

`1.6pi^(2)m//s^(2)`

D

`0.4 pi m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`a=(v^(2))/(r ) = omega^(2) r = 4pi ^(2) n^(2) r = 4pi ^(2) xx 1xx0.4 = 1.6 pi ^(2) m//s^(2)`
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