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A particle is moving along a circle ...

A particle is moving along a circle of radius 1 m at a speed of 2 m/s .If the speed is incresed at the rate of 3 `m//s^(2)` then the resultant acceleration is

A

`2m//s^(2)`

B

`3m//s^(2)`

C

`5 m//s^(2)`

D

`10 m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`a_(T) = 3m//s^(2) , a_(c ) =(v^(2))/(r ) =(4)/(1) = 4 `
` a _(R ) = sqrt( a_(c )^(2) +aT _(2) ^(2) )=sqrt(3^(2)+4^(2))=5`
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