A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is
A
`(2 pi v) /(T) `
B
`(2pi r )/(T )`
C
`(2pi r^(2))/(T )`
D
`(2pi v^(2))/(T )`
Text Solution
Verified by Experts
The correct Answer is:
A
C.P acceleration `=(v^(2))/(r ) = v((v)/(r ))=v omega ` ` therefore a= v ((2pi )/(T ))=(2 pi v)/(T)`
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