Home
Class 12
PHYSICS
A particle of mass m describes a circle ...

A particle of mass `m` describes a circle of radius `r` . The centripetal acceleration of the particle is `(4)/(r^(2))` . What will be the momentum of the particle ?

A

`(2m)/(r )`

B

`(r )/(sqrt(2m))`

C

`(2m)/(sqrt(r ))`

D

`(R )/(2m)`

Text Solution

Verified by Experts

The correct Answer is:
C
`a_(c ) =(v^(2) )/(r ) =(4) /(r^(2)) " " therefore v^(2) =(4pi )/(r^(2) =(4) /(r ) therefore v =(2) /( sqrt(r ))`
Linear momentum `=mv =(2m ) /( sqrt(r ))`
Promotional Banner

Topper's Solved these Questions

  • CIRCULAR MOTION

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP-1|1 Videos

  • CIRCULAR MOTION

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP-2|1 Videos

  • ATOMS, MOLECULES AND NUCLEI

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|30 Videos

  • COMMUNICATION SYSTEMS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP -20|10 Videos

Similar Questions

Explore conceptually related problems

A particle of mass m describes a circle of radius r with a uniform speed v. The centripetal acceleration of the pariticle is 4 / r^(2) .What is the magnitude of the linear momentum of the particle ?

A particle of mass m is moving on a circular path of radius r . Centripetal acceleration of the particle or radius r . Centripetal acceleration of the particle depends on time t according to relation a_(c ) = kt^(2) . What power is delievered to the particle ?

A particle is moving at uniform speed 2 ms^(-1) along a circle of radius 0.5m .The centripetal acceleration of particle is

If KE of the particle of mass m performing UCM in a circle of radius r is E. Find the acceleration of the particle

A particle of mass m is moving in a circle of radius r. The centripetal acceleration (a_(c)) of the particle varies with the time according to the relation, a_(c)=Kt^(2) , where K is a positive constant and t is the time. The magnitude of the time rate of change of angular momentum of the particle about the centre of the circle is

A particle with the constant speed in a circle of radius r and time period T.The centripetal acceleration of a particle is

A particle moves in a circle of radius 25 cm at two revolutions per sec. The acceleration of the particle in m//s^(2) is:

A particle is moving on a circular path of radius 0.3 m and rotaing at 1200 rpm. The centripetal acceleration of the particle