A car is moving on a circular path and takes a turn. If `R_(1)` and `R_(2)` be the reactions on the inner and outer wheels, respectively, then
A
`R_(1) = R_(2) `
B
`R_(1) lt R_(2)`
C
`R_(1) gt R_(2)`
D
`R_(1) ge R_(2)`
Text Solution
Verified by Experts
The correct Answer is:
B
Suppose that a car of mass M is moving in a circular path of radius r, with a speed v. h= height of the centre of gravity of the from the road level 2a = distance between the centres of the wheels of the car Let `R_(1 ) and R_(2)` are given by `R_(1) =1/2 M[g-(v^2h)/(ra)]` `R_(2) = 1/2M[g+(v^2h)/(ra)]` thus we find than ` R_(1) lt R_(2)` Note: When the speed increases beyond a certain limit the car overturns and its inner wheel leaves the ground first .
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