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A particle of mass m describes a circ...

A particle of mass m describes a circle of radius r with a uniform speed v. The centripetal acceleration of the pariticle is `4 / r^(2) ` .What is the magnitude of the linear momentum of the particle ?

A

`(2m)/(sqrt(r ))`

B

`(2m)/( r )`

C

`(4m)/( sqrt( r) )`

D

` (4m) /(r )`

Text Solution

Verified by Experts

The correct Answer is:
A
The C.P acceleration ,
`a= (v^(2))/(r ) = (4) /(r^(2)) " " therefore V^(2) =(4)/(r therefore v= (2)/(sqrt(r ))`
` therfore ` the momentum `p =mv =(2m)/(sqrt(r ))`
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