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A cyclist goes round a circular path of ...

A cyclist goes round a circular path of circumference `34.3 m "in" sqrt22 s`.The angle made by him , with vertical , is

A

`45^@`

B

`44^(@)`

C

`43^(@)`

D

`41^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A
`v=(2pi r)/(T ) = ( 34.3)/(sqrt(22))and `
`r= ("circumference ")/(2pi)=(34.3)/(2xx22//7)`
` therefore tan theta = (v^(2))/(rg ) =( 34.3xx34.3xx22xx2)/(22xx34.3xx7xx9.8)=1`
` therefore tan theta =1 therefore theta = 45^(@)`
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