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The radius of curvature of a metre gauge...

The radius of curvature of a metre gauge railway line at a place where the train is moving at `36km //h` is 50 m .If there is no side thrust on the rails , then the elevation of the outer rail above the inner rail will be `(g=10m//s^(2))`

A

`0.1 m`

B

`0.2m`

C

`0.3m`

D

`0.4m`

Text Solution

Verified by Experts

The correct Answer is:
B
`theta = tan ^(-1) ""(v^(2))/(rg)) and h=l sin theta theta = 0.2 m `
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