A motor cylist moving with a velocity of 72 km / hour on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 m . The acceleration due to gravity is 10 `m // sec ^(2) ` . In order to avoid skidding , he must not bend with respect to the vertical plane by an angle greater than
A
`theta = tan ^(-1) 6`
B
`theta = tan ^(-1) 2`
C
`theta = tan ^(-1) 25.92`
D
`theta = tan ^(-1) 4`
Text Solution
Verified by Experts
The correct Answer is:
B
v= 72 km /h = 20 m/s Angle of bending ` theta ` is given by `tan theta = (v^(2))/(rg ) =(20xx20 )/(20xx10)=2 ` ` therefore theta = tan ^(-1) (2) ` ` therefore ` He should not bend w.r.t the vertical by an angle ` theta gt tan ^(-1) 2 .`
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