The minimum velocity (in ms^(-1))` with which a car driver must traverse a flat curve of radius 150m and coefficient of friction 0.6 to avoid skidding is
A
30
B
25
C
60
D
15
Text Solution
Verified by Experts
The correct Answer is:
A
`(mv ^(2))/(r ) =F = mu R = mu mg ` ` therefore v^(2) = mu r g ` ` therefore v= sqrt( mu r g ) = sqrt( 0.6 xx 150 xx10 ) = 30 m//s `
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