the maximum velocity with which a driver a must drive his car on a flat curved road of radius of curvature 150 m and coefficient of friction 0.6 to avoid the skidding of his car is ( take `g=10 m//s^(2))`
A
60m/s
B
50 m/s
C
40 m/s
D
30 m/s
Text Solution
Verified by Experts
The correct Answer is:
D
The C.F force `(mv^(2))/( r ) ` acting on the car of mass m is opposed by the force of friction `F= mu R = mu m g ` TO avoid skidding ,` ( mv^(2))/( r ) le ,mu m g ` ` therefore ` The maximum speed is given by ` (mv ^(2)m) /(r ) = mu mg ` ` therefore v _m^2= mu mg = 0.6 xx150 xx10 = 900` ` therefore v_(m ) = sqrt( 900 ) = 30 m//s`
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