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A weightless thread can support tension ...

A weightless thread can support tension up to `30N.A` particle of mass `0.5kg` is tied to it and is revolved in a circle of radius `2m` in a verticle plane. If `g=10m//s^(2)`, then the maximum angular velocity of the stone will be

A

`3rad//s`

B

`4rad//s`

C

`5 rad//s`

D

`6 rad//s`

Text Solution

Verified by Experts

The correct Answer is:
C

when a stone attached to a weightless thread is revvolved in a vertical circle , the tension in the string is maximum when it is at the lowest point .
Max . Tension `= (mv ^(2))/( r ) + mg = mr omega ^(2) + mg `
` therefore T- mg = mr omega ^(2)`
` 30-0.5 xx10=0.5 xx2xxomega^(2)`
`25=omega ^(2) therefore omega = 5 rad //s `
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