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A mass m is kept hanging by a rad ...

A mass m is kept hanging by a rad of length L. What tangential velocity must be given to it so that it can just reach the top of the vertical circle ?

A

`5sqrt(gL)`

B

`4sqrt(gL)`

C

`3sqrt(gL)`

D

`2sqrt(gL)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(1) /(2 ) mv ^(2) = mg (2L ) therefore v= 2 sqrt( gL ) `
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Knowledge Check

  • A mass m is hanging by a string of length l. The velocity v_(0) which must be imparted to it to just reach the top is

    A
    `sqrt3gl`
    B
    `sqrt4gl`
    C
    `sqrt5gl`
    D
    `sqrt6gl`

  • A simple pendulum of effective length 'l' is kept in equilibrium in vertical position . What horizontal velocity should be given to its bob , so that it just completes a vertical circular motion ?

    A
    `sqrt(5gl) `
    B
    `sqrt(3gl)`
    C
    `sqrt(gl)`
    D
    `sqrt(7gl)`

  • The maximum velocity at the lowest point, so that the string just slack at the highest point in a vertical circle of radius l.

    A
    `sqrt(gl)`
    B
    `sqrt(3gl)`
    C
    `sqrt(5gl)`
    D
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