If T and T' are the periods of a simple pendulum and a conical pendulum of the sample length then .
A
`T=T'`
B
`Tlt T'`
C
`T gt T'`
D
`T=(1)/(2) T'`
Text Solution
Verified by Experts
The correct Answer is:
C
`T sin theta = (mv^(2))/( r) , T cos theta = mg ` ` therefore ((mv^(2))/(r ))/(mg) = tan theta ` ` therefore (mv^2)/( r) = mg tan theta = mg (r ) /( sqrt(L^(2)-r^(2)))`
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