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A body of mass 500 gram is rotating ...

A body of mass 500 gram is rotating in a vertical of radius 1 m . What is the difference in its kinetic energies at the top and the bottom of the circle ?

A

`4.9 J`

B

`19.8 J`

C

`2.8 J`

D

`-9.8 J`

Text Solution

Verified by Experts

The correct Answer is:
B

Diff .In . K.E at the bottom and at the top
` =(1)/(2) m (v_(1)^(2)-v_(2)^(2)) "But " v_(1) sqrt(5 gr ) and v_(2) = sqrt( gr)`
`=(1)/(2) m ( 5 gr 0 gr) = 2 mgr = 2xx(1)/(2) xx9.8 xx1`
`=9.8J`
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