A weightless thread can bear tension upto 3.7 kg wt .A stone of mass 500 gm is tied to it and rotated in a circular path of radius 4 m, in a vertical circle If ` g=10 m//s^(2)` then the maximum angular velocity of the stone will be
A
3
B
4
C
5
D
6
Text Solution
Verified by Experts
The correct Answer is:
B
`T_(max) = mg + mr omega ^(2) ` at the lowest point `3.7xx10=0.5xx10+0.5xx4xxomega^(2)` `therefore 37-5=2 omega ^(2) " " therefore omega = 4 rad //s`
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