A body of mass 0.1 Kg attached at the end of a string 6m long , is whirled in a vertical circle . The tension in the string is 6.4 N at the lowest point . What is the maximum angular velocity the body ? `(g=10 m//s^(2))`
A
12 rad /s
B
9 rad/s
C
6 rad /s
D
3 rad /s
Text Solution
Verified by Experts
The correct Answer is:
D
At the lowest point , T - mg = `mr omega^(2)` ` therefore 6.4-0.1xx10=0.1xx6xxomega ^(2)` ` therefore omega^(2 ) = ( 5.4)/(0.6) = 9 " " therefore omega = 3 rad //s`
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