What is the apparent of a body of mass m attached at the end of a string and which is just completing the loop in a vertical circle , at the lowest point in its path ?
A
`0`
B
`mg`
C
`3 mg`
D
`6 mg`
Text Solution
Verified by Experts
The correct Answer is:
D
The apparent weight of the body moving in a vertical circle is the tension in the string . When it is at the lowest point , `T_(1) = (mv^2)/(r ) +mg ` But for just completing the vertical circle , it should be given a velocity ` v= sqrt(5gr)` ` therefore T_1 = (m)/(r ) = (5gr) +mg = 5 mg +mg = 6 mg `
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