A racing car competes 5 rounds of a circular track in 2 minute . What is the radius of the track if the car has uniform centripetal acceleration of `pi ^(2) m//s ^2` ?
A
120m
B
144m
C
160m
D
80m
Text Solution
Verified by Experts
The correct Answer is:
B
Period of revolution `,T=(2xx60)/( 5 ) = 24 s` `C.P ` acceleration `= (v^2)/(r )= r omega ^2 = r . (4pi^2)/(T^2)` ` therefore pi ^(2) = (4 pi ^(2)r)/(T^(2)) " " therefore r= (T^(2))/(4)=(24xx24)/(4) =144m`
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