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In vertical circular motion, the ratio o...

In vertical circular motion, the ratio of kinetic energy of a particle at highest point to that at lowest point is

A

5

B

2

C

`0.5`

D

`0.2`

Text Solution

Verified by Experts

The correct Answer is:
D
for the particle , `V_(L ) = sqrt(5gr) and v_(H )= sqrt(gr)`
`:' K.E =1/2 mv^2 , K_(H) =1/2 mv_(H )^(2)=(1)/(2) mg r `
` and K_(L ) =(1)/(2) mv^(L )^(2)=(1)/(2).5mgr `
` therefore (K_(H))/(K_(L)) =(1/2 mgr)/(1/2m(5gr))=1/5=0.2`
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