Home
Class 12
PHYSICS
If the potential energy is minimum for t...

If the potential energy is minimum for two atoms at `r_(0) = 0.75 Å`. This is the equilibrium distance. Then,

A

the force is attractive at = r = 0.5 Å

B

the force is attractive at = r = 0.75 Å

C

the force is repulsive at r = 0.5 Å

D

the force is repulsive at r = 0.75 Å

Text Solution

Verified by Experts

The correct Answer is:
C
The P.E. is minimum when the interatomic distance is `r_(0) = 0.75 Å`
When `r lt r_(0) (0.5 Å lt 0.75 Å)`, the force is repulsive.
When `r gt r_(0)`, the force is attractive.
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY

    MARVEL PUBLICATION|Exercise Test Your Grasp - 5|15 Videos

  • CURRENT ELECTRICITY

    MARVEL PUBLICATION|Exercise MCQ|151 Videos

  • ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENTS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP - 16|30 Videos

Similar Questions

Explore conceptually related problems

Statement I : For the stable equilibrium force has to be zero and potential energy should be minimum. Statement II : For the equilibrium it is not necessary that the force is not zero.

If the potential energy between two molecules is given by U= -(A)/(r^6) + B/(r^(12)) , then at equilibrium , separation between molecules , and the potential energy are :

What will be the energy corresponding to the first excited state of a hydrogen atom if the potential energy of the atom is taken to be 10eV when the electron is widely separated from the proton ? Can be still write E_(0) - E_(1)//n^(2), or, r_(n) = a_(0) n^(2) ?

These diagrams represent the potential energy U of a diatomic molecule as a function of the inter-atomic distance r . The diagram corresponds to stable molecule found in nature is.