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The breaking stress of a cylindrical rod...

The breaking stress of a cylindrical rod is `10^(6) N//m^(2)`. If the maximum possible height of the rod is 10 m, then the density of the material of the rod is [use `g = 10m//s^(2)`]

A

`10^(3) kg//m^(3)`

B

`2 xx 10^(3) kg//m^(3)`

C

`10^(4) kg//m^(3)`

D

`2 xx 10^(4) kg//m^(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
Breaking stress `= (F)/(A) = (mg)/(A) = (v xx rho xx g)/(A)`
`= (A h rho g)/(A) = h rho g`
`:. rho = ("Breaking stress")/(h g) = (10^(6))/(10 xx 10) = 10^(4) kg//m^(3)`
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