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The area of cross section of a steel wir...

The area of cross section of a steel wire `(Y=2.0 xx 10^(11) N//m^(2))` is `0.1 cm^(2)`. The force required to double is length will be

A

`2xx10^(10) N`

B

`2xx10^(12) N`

C

`2xx10^(11) N`

D

`2xx10^(6) N`

Text Solution

Verified by Experts

The correct Answer is:
D
Strain `= l/L = 1`
`:. F = AY=0.1xx10^(-4)xx2xx10^(11) = 2xx10^(6) N`
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