Home
Class 12
PHYSICS
Find the change in volume of a lead bloc...

Find the change in volume of a lead block of volume 2 `m^(3)` Which is subjected to pressure of 20 atm. (Take, 1 atm `= 1.013 xx 10^(5) N//m^(2)` and bulk modulus `= 8 xx 10^(9) N//m^(2)`)

A

`3 xx 10^(8) N//m^(2)`

B

`5 xx 10^(7) N//m^(2)`

C

`6 xx 10^(8) N//m^(2)`

D

`8 xx 10^(8) N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`K = (Vdp)/(dv) :. dp = (Kdv)/(v) = 6xx10^(9) xx (10)/(100)`
`= 6xx10^(8) N//m^(2)`
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY

    MARVEL PUBLICATION|Exercise Test Your Grasp - 5|15 Videos

  • CURRENT ELECTRICITY

    MARVEL PUBLICATION|Exercise MCQ|151 Videos

  • ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENTS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP - 16|30 Videos

Similar Questions

Explore conceptually related problems

Compute the fractional change in volume of a glass slab, when subjicted to a hydrautic pressure of 10 atmosphere. Bulk modulus of elasticity of glass = 37 xx 10^(9) Nm^(-2) and 1 atm = 1.013 xx 10^(5)Pa .

A spherical ball contracts in volume by 0.0098% when subjected to a pressure of 100 atm. Calculate its bulk modulus. Given 1 atm =1.01xx10^(5) Nm^(-2) .

For a metal Y = 1.1xx10^(10) N//m^(2) and Bulk modulus is K = 11xx10^(10) N//m^(2) then Poisson's ratio is (nearly)

A glass slab is subjected to a pressure of 10 atm. The fractional change in its volume is (Bulk modalus of glass =37 xx 10^(9) Nm^(-2), 1 atm= 1 xx 10^(5) N m^(-2) )

Calculate the volume change of a solid copper cube, 40 mm on each edge, when subjected to a pressure of 2xx10^(7) Pa. The bulk modulus for copper is 1.25xx10^(11) Nm^(-2) .

A hydraulic press contains 0.25 m^(3)(250L) of oil. Find the decrease in volume of the oil wen it is subjected to a pressure increase /_\p=1.6xx10^(7)Pa . The bulk modulus of the oil is B=5.0xx10^(9)Pa .

Compute the fractional change in volume of a glass slab, when subjected to a uniform pressure of 1.013xx10^(6)Pa . Bulk modulus of elasticity of glass =37xx10^(9)Nm^(-2) .

The bulk modulus of water if its volume changes from 100litres to 99.5 litre under a pressure of 100atm is (Take 1atm=10^5Nm^-2 )

A spherical ball of volume 1000 cm^(3) is subjected to a pressure of 10 atomosphere. The change in volume is 10^(-2)cm^(-3) . IF the ball is made of iron find its bulk modulus. (Atmospheric pressure = 1xx10^(5) Nm^(-2) )

The pressure required to reduce the given volume of water by 1% is, (Bulk modulus of water =2xx10^(9)N//m^(2) )