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A tangential force of 2100N is applied o...

A tangential force of `2100N` is applied on a surface area `3xx10^(-6) m^(2)` which is `0.1m` form fixed surface. The force produces a shift of `7m` of upper surface with respect to bottom. Calcualte the modulus of rigidity fo the material.

A

`10^(9) N//m^(2)`

B

`10^(10) N//m^(2)`

C

`10^(11) N//m^(2)`

D

`5xx10^(10) N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`theta = (x)/(L) = (7 xx 10^(-3))/(0.1) = 7 xx 10^(-2)`
`:. eta = (F)/(A theta) = (2100)/(3 xx 10^(-6) xx 7 xx 10^(-2)) = 10^(10) N//m^(2)`
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