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The increase in length of a wire on stre...

The increase in length of a wire on stretching is `0.04%`. If its Poisson's ratio is 0.5, the diameter is reduced by

A

0.0001

B

0.0005

C

0.0004

D

0.0002

Text Solution

Verified by Experts

The correct Answer is:
D
`(delta L)/(L) = (4)/(100 xx 100) = 4 xx 10^(-4)`
`:. (delta D)/(D) = sigma(delta L)/(L) = (1)/(2) xx 4 xx 10^(-4) = 2 xx 10^(-4)`
`:. (delta D)/(D) = (0.02)/(100) = 0.02%`
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