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To compress a liquid by 10% of its origi...

To compress a liquid by `10%` of its original volume, the pressure required is `2xx10^(5) N//m^(2)`. The bulk modulus of the liquid is

A

`2xx10^(4) N//m^(2)`

B

`2xx10^(5) N//m^(2)`

C

`2xx10^(7) N//m^(2)`

D

`2xx10^(6) N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`K = V(dP)/(dV) = (2 xx 10^(5))/(1//10) = 2 xx 10^(6) N//m^(2)`
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