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A metallic rod breaks when strain produc...

A metallic rod breaks when strain produced is `0.2%`. The Young's modulus of the material of the rod is `7xx10^(9)N//m^(2)`. What should be its area of cross-section to support a load of `10^(4)N` ?

A

`7.15xx10^(-4) m^(2)`

B

`3.15xx10^(-5) m^(2)`

C

`2xx10^(3) m^(2)`

D

`12xx10^(-4) m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Breaking Stress `= Y xx "Breaking Strain"`
`= 7 xx 10^(9) xx (0.2)/(100) = 1.4 xx 10^(7)`
Breaking stress `= ("Breaking force")/("area")`
`:. A = ("Breaking force")/("Breaking stress") = (10^(4))/(1.4 xx 10^(7))`
`= 7.15 xx 10^(-4) m^(2)`
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