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The increase in pressure in kPa requried...

The increase in pressure in kPa requried to decrease 200 litre volume of a liquid by 0.004% is (bulk modulus of the liquif = 2100 Mpa)

A

84

B

`92.4`

C

`8.4`

D

168

Text Solution

Verified by Experts

The correct Answer is:
A
`K = 2100 xx 10^(6) Pa`
`dV = (0.004)/(100) xx 200, V = 200 L = 200 xx 10^(3) = 0.008L`
`because K = V(dP)/(dV)`
`:. dP = K(dV)/(V) = 2100 xx 10^(6) xx (0.008)/(200)`
`= 21 xx 10^(6) xx (8)/(2) xx 10^(-3)`
`= 84 xx 10^(3) Pa = 84 kPa`
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