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For a metal Y = 1.1xx10^(10) N//m^(2) an...

For a metal `Y = 1.1xx10^(10) N//m^(2)` and Bulk modulus is `K = 11xx10^(10) N//m^(2)` then Poisson's ratio is (nearly)

A

0.25

B

`0.30`

C

0.35

D

0.4

Text Solution

Verified by Experts

The correct Answer is:
D
`:. (Y)/(3) = 1 - 2 sigma :. sigma = (1)/(2)[1-(Y)/(3K)]`
`:. sigma = (1)/(2)[1-(7.2 xx 10^(10))/(3 xx 12 xx 10^(10))]`
`:. sigma = (1)/(2)[1-(7.2)/(36)] = (1)/(2)[1-0.2]`
`= (1)/(2) xx 0.8 = 0.4`
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