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If a wire having initial diameter of 2 m...

If a wire having initial diameter of 2 mm produced the longitudinal strain of `0.1%`, then the final diameter of wire will be `(sigma=0.5)`

A

1.999 mm

B

1.990 mm

C

2.001 mm

D

2.010 mm

Text Solution

Verified by Experts

The correct Answer is:
A
`sigma = ("Lateral Strain")/("Longitudinal Strain")`
`0.5 = ((delta D)/(D))/(10^(-3))` [`delta D` is the decrease in diameter.]
`:. 5 xx 10^(-4) = (delta D)/(D)`
`:. Delta D = 2 xx 5 xx 10^(-4) = 10^(-3) mm = 0.001 mm`
`:.` Final diameter `= 2 - 0.001 = 1.999 mm`
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