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The force constant of a wire is K and th...

The force constant of a wire is K and that of another wire of the same material is 2K. When both the wires are stretched by the same force, then the relation between the works done in the two cases is

A

`W_(2) = W_(1)`

B

`W_(2) = 0.5 W_(1)`

C

`W_(2) = 2W_(1)`

D

`W_(2) = 2W_(1)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`x_(1) = (F)/(K) , x_(2) = (F)/(2K) :. x_(2) = (x_(1))/(2)`
`because W_(1) = Fx_(1) and W_(2) = Fx_(2) :. W_(2) = 0.5 W_(1)`
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Knowledge Check

  • The force constant of a wire is k and that of another wire is . 2k When both the wires are stretched through same distance, then the work done

    A
    `W_(2)=2W_(1)^(2)`
    B
    `W_(2)=2W_(1)`
    C
    `W_(2)=W_(1)`
    D
    `W_(2)=0.5W_(1)`
  • Two wires of the same material and same mass are stretched by the same force. Their lengths are in the ratio

    A
    `3:2`
    B
    `2:3`
    C
    `4:9`
    D
    `9:4`
  • The ratio of radii of two wires of same material is 2 : 1. If they are stretched by the same force, the ratio of their stress is

    A
    `2 : 1`
    B
    `1 : 2`
    C
    `1 : 4`
    D
    `4 : 1`
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