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When a 4kg mass in hung vertically from ...

When a 4kg mass in hung vertically from a light spring that obeys Hooke's low, the spring stretches by 2 cm. The work that should be done by an external agent in stretching this spring by 5 cm will be (use `g = 10 m//s^(2)`)

A

1.5 J

B

1.75 J

C

2 J

D

0.9 J

Text Solution

Verified by Experts

The correct Answer is:
D
`K = (F)/(x) = (4 xx 10)/(0.2) = 2000 kg//m`
`W = (1)/(2) Kx^(2) = 2.5 J`
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