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If the potential energy of a spring is V...

If the potential energy of a spring is V on stretching it by `2 cm`, then its potential energy when it is stretched by `10 cm` will be

A

`(U)/(5)`

B

`(U)/(25)`

C

25 U

D

5 U

Text Solution

Verified by Experts

The correct Answer is:
C
If a spring is stretched by a distance x, its
`P.E. = (1)/(2)Kx^(2)`
`:. (U_(2))/(U_(1)) = ((x_(2))/(x_(1)))^(2) = ((10)/(2))^(2) = 25`
`:. U_(2) = 25 U_(1)` or `U_(2) = 25 U`
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