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When the load applied to stretch a wire ...

When the load applied to stretch a wire is increased from 1kg-wt to 2kg-wt, the extention produced in the wire increases from 0.5 mm to 1mm. The work done in the extenstion of the wire is `(g = 10 m//s^(2))`

A

`2.5 xx 10^(-3) J`

B

`1.87 xx 10^(-3) J`

C

`7.5 xx 10^(-3) J`

D

`1.5 xx 10^(-3) J`

Text Solution

Verified by Experts

The correct Answer is:
C
`W = W_(2) - W_(1) = (1)/(2) [M_(2) g_(2)l_(2) - M_(1)g_(1)l_(1)]`
`= (1)/(2) [ 2 xx 10 xx 10^(-3) -1 xx 10 xx 0.5 xx 10^(-3)]`
`= (1)/(2) xx 10^(-3) (15) = 7.5 xx 10^(-3) J`
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