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A wire of uniform cross-sectional area A...

A wire of uniform cross-sectional area A and young's modulus Y is stretched within the elastic limits. If s is stress in the wire, the elastic energy density stored in the wire in terms of the given parameters is

A

`(8)/(2Y)`

B

`(2Y)/(s^(2))`

C

`(s^(2))/(2Y)`

D

`(s^(2))/(Y)`

Text Solution

Verified by Experts

The correct Answer is:
C
Elastic energy density `= ("Elastic energy")/("Volume") = (1)/(2) (("stress")^(2))/(Y)`
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