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A small currnet-carrying element of 1 cm...

A small currnet-carrying element of 1 cm carries a current 4 A. The magnetic field induction due to the current element at a distancwe 10 cm from it is `2xx 10^(-7).` T. What is the angle between the direction of the current and the line joining the current elemetn to the point ?
[Take `mu_(0)=4pi xx10^(-7) Wb^(-1)m^(-1)]`

A

`90^(@)`

B

`60^(@)`

C

`45^(@)`

D

`30^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`dl =1 cm =10^(-2)m, I=4A, r =10^(-1)m`
`because dB =(mu_(0))/(4pi) ((Idl sin theta)/(r ^(2)))`
`therefore2xx10^(-7) =(10^(-7)xx4xx10^(-2)xxsin theta)/((10^(-1))^(2))`
`therefore 2 sin theta =1 therefore sin theta =1/2 therefore theta =30^(@)`
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