A coil of 10 cm radius, carrying a curre...

A coil of 10 cm radius, carrying a current of 1 A produces magnetic field of induction `6.284xx10^(-3)Wb//m^(2)` at its cente. What is the number of turns of the coil ?

100

200

500

1000

Text Solution

Verified by Experts

The correct Answer is:

`B= (mu_(0))/(4pi)((2pin I)/(r))`
` 6.284 xx10^(-3) =(10^(-7)xx2xx3.142xxnxx1)/(10^(-1))`
`thereforen =(6.284xx10^(-4))/(10^(-7)xx2xx3.142)=10^(3)=1000`

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