A current carrying conductior of length 2 m is bent in the form of an orc of a circle of radius 80 cm. The magnetic induction at the centre of curvature of the arc is found to be `2xx10^(-6)Wb//m^(2).` What is the current following through the conductor ?

Options

A. `3.2A`
B. `6.4A`
C. `4.8A`
D. `9.6A`

Answer

B

Explanation

`B= (mu_(0))/(4pi) (Il)/(r ^(2))` where l is the length of the conductor.
`therefore 2xx 10^(-6) =(10^(-7) xx64xx10^(-2))/(2xx10^(-7))=6.4A`