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A particle carrying a charge equal to 10...

A particle carrying a charge equal to `100` times the charge on an electron is rotating per second in a circular path of radius `0.8 metre`. The value of the magnetic field produced at the centre will be (`mu_(0)=` permeability for vacuum)

A

`10^(-3) mu_(0)`

B

`10^(-11) mu _(0)`

C

`10^(-7)mu_(0)`

D

`10^(-17)mu_(0)`

Text Solution

Verified by Experts

The correct Answer is:
D

A revolving charge is equivalent to a current carrying coil, The current = charge `xx` frequency
`thereforeI =100xxe xx1 =100e " "[because I = Q/T=nQ]`
`therefore B = (mu_(0)I)/(2E) =(mu_(0) xx100xx1.6 xx10^(-19))/(2xx0.8)`
`therefore B = 10^(-17)mu_(0)`
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