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When a charged particle moving with vel...

When a charged particle moving with velocity `vec(V)` is subjected to a magnetic field of induction `vec(B)` the force on it is non-zero. This implies that:

A

angle between `vecv and vecB` is necessarily `90^(@)`

B

angle between `vecv and vecB` can have any value other than `90^(@)`

C

angle between `vecv and vecB` is either zero or `180^(@)`

D

angle between `vecv and vecB` is either zero or `180^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C

The magnitude of dorce acting on a charged particle moving with a velocity `vec v` in a magnetic field `vecB,` is given by
`F= qvB sin theta` where `theta` is the angle between `vec c and vecB`
If `theta=0^(@) or 180^(@) , F=0`
But it is given that F is not zero.
This implies that angle `theta` between `vec v and vecB` can have any value other than `0^(@) and 180^(@).`
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