A long straight wire carries a current of 10 A. An electron travels perpendicular to the plane of this wire at a distance 0.1 m with a velocity of `5.0 xx10^(6)m//s.` What is the force acting on the electron due to the current in wire ?

Options

A. ` 2.2 xx10^(-17)N`
B. `1.6xx10^(-17) N `
C. `0.6xx10^(-17)N`
D. Zero

Answer

D

Explanation

Force `F= q (vecv xx vecB) or vecF = - e(vecvxx vecB)`
`therefore F =-evB sin theta`
The electron travels perpendicular to the plane of the wire.
`therefore` Angle `theta` between `vecVand vevB` is either `0^(@) or 180^(@).`
`therefore sin theta = 0 and F=0`