An `alpha` particel is projected with a velocity of `10^(7)` m/s, in a unifform magnetic fiedl on inductin, `1.2xx10^(-6)Wb//m^(2),` in a direction perpendicular to the field. If the lateral force acting on the particle is `3.84xx10^(-18)N,` what is the charge onn the a particle ?

Options

A. `1.6xx10^(-19)C`
B. `2.4xx10^(-19)C`
C. `3.2xx10^(-9) C`
D. `4xx10^(-19)C`

Answer

C

Explanation

`G=qvB sin theta but theta =90^(@)`
`therefore q= (F)/(Bv) =(3.84xx10^(-18))/(1.2xx10^(-6)xx10^(7))`
`q=3.2 xx10^(-19)C`
Note : `alpha` particle carries a charge of 2e
`=2 xx1.6 xx10^(-19) C=3.2 xx10^(-19)C`