When n-butyl magnesium iodide is treated with water the product obtained is

Options

A. Isobutane
B. n-butane
C. Butene
D. Propane

Explanation

To solve the question of what product is obtained when n-butyl magnesium iodide is treated with water, we can follow these steps:

### Step 1: Identify the Reactants
We start with n-butyl magnesium iodide (n-BuMgI). This compound is a Grignard reagent, which is characterized by the presence of a carbon-magnesium bond.

### Step 2: Understand the Nature of Grignard Reagents
Grignard reagents are highly reactive and behave as nucleophiles. They can react with compounds that have acidic hydrogen atoms. Water (H₂O) contains acidic hydrogen, making it a suitable reactant for Grignard reagents.

### Step 3: Reaction Mechanism
When n-butyl magnesium iodide is treated with water, the following reaction occurs:
- The n-butyl group (C₄H₉) from the Grignard reagent acts as a base and abstracts a proton (H⁺) from water.
- This results in the formation of n-butane (C₄H₁₀) and magnesium hydroxide iodide (Mg(OH)I).

### Step 4: Write the Chemical Equation
The reaction can be summarized in the following equation:
\[ \text{n-BuMgI} + \text{H}_2\text{O} \rightarrow \text{n-BuH} + \text{Mg(OH)I} \]

### Step 5: Identify the Product
The main product of this reaction is n-butane (C₄H₁₀), which is formed as a result of the protonation of the n-butyl carbanion.

### Final Answer
When n-butyl magnesium iodide is treated with water, the product obtained is n-butane (C₄H₁₀).

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