Reaction of t-butyl bromide with alcoholic KOH products

Options

A. Isobutane
B. Isobutylene
C. Sodium t-butoxide
D. t-butylmethylether

Explanation

To determine the products of the reaction between t-butyl bromide (tert-butyl bromide) and alcoholic KOH, we can follow these steps:

### Step 1: Identify the structure of t-butyl bromide
T-butyl bromide is a tertiary alkyl halide with the formula (CH₃)₃CBr. The structure can be represented as follows:
```
Br
|
CH₃ - C - CH₃
|
CH₃
```
Here, the central carbon atom is bonded to three methyl groups (CH₃) and one bromine atom (Br).

**Hint:** Remember that tertiary halides have a carbon atom bonded to three other carbon atoms.

### Step 2: Understand the role of alcoholic KOH
Alcoholic KOH acts as a strong base and promotes elimination reactions (dehydrohalogenation). In this reaction, KOH will abstract a hydrogen atom from a carbon adjacent (alpha) to the carbon bonded to bromine, leading to the elimination of HBr.

**Hint:** Alcoholic KOH is used for elimination reactions rather than substitution reactions.

### Step 3: Identify the alpha hydrogens
In t-butyl bromide, the alpha carbons are those adjacent to the carbon bonded to bromine. Since there are three equivalent alpha carbons (each bonded to a hydrogen), we can remove a hydrogen from any of these positions.

**Hint:** Look for hydrogens on the carbons next to the carbon that has the bromine attached.

### Step 4: Perform the elimination reaction
When one of the alpha hydrogens is removed along with the bromine, a double bond is formed between the carbon that was bonded to bromine and the carbon from which the hydrogen was removed. The reaction can be summarized as follows:
- Remove Br from the tertiary carbon.
- Remove H from one of the alpha carbons.
- Form a double bond between the two carbons.

This results in the formation of isobutylene (2-methylpropene):
```
CH₃
|
CH₂ = C
|
CH₃
```

**Hint:** The product will be an alkene due to the formation of a double bond.

### Step 5: Write the final product
The final product of the reaction between t-butyl bromide and alcoholic KOH is isobutylene (2-methylpropene).

**Hint:** Make sure to name the product correctly based on the structure you have drawn.

### Conclusion
The product of the reaction of t-butyl bromide with alcoholic KOH is isobutylene.

**Final Answer:** Isobutylene (2-methylpropene)